IP = (Minutes) x (2.035) + 18
This is if you complete and win the match.
Minutes < 56

IP = (Minutes) x (1.402) + 16
This is if you complete and loose the match.
Minutes < 56


Example:
Win a game of summoner's rift in 40 minutes:
IP = (40) x (2.035) + 18 = 92.2 + 18 = 110.2 IP rounded down to 110 IP.

Chance of winning a ranked game in solo queue:
Assuming you are not a troll / are a good player.

Troll = (1400 / Your Rating) x (40% - 10%(Your Rating / 1400))
Troll = (1400 / 1269) x (40% - 10%(1269 / 1400) = 34.13%
Troll on other team = Troll x 1.25
Troll Other = 34.12% x 1.25 = 42.66%

Chance of winning = 50% + (Troll Other - Troll)% = 50% + (42.66% - 34.12%) = 50% + 8.54% = 58.54%
Now since you are low elo, if we add the Master Yi afk push top lane your chance of winning is now: 90% + (Troll Other - Troll) or 98.54%

In theory, what is the efficiency of a woodchuck by himself as opposed to a family of 8 woodchucks when chucking wood assuming an average level of wood being chucked?

A woodchuck would chuck as much as a woodchuck could chuck.
Therefore with a family of 8 woodchucks chucking as much wood as they could chuck then they would chuck 8 times the amount of wood as a lone woodchuck could.

What are the chances that I will get elo job kids in my next 1800 match?

How are you making these numbers up anyways? Seems almost arbitrary except for the 1400 elo thing and it seems oversimplified, not taking many external variables to account.

quadratic formula

LOL. Pro! Made my day sir.

X = (-b +/2 sqrt(b^2 - 4ac)) / 2a

http://www.youtube.com/watch?v=D_0vgqi7fU4

My numbers are always right.

Chance of running into a booster:
[(Your elo x .75) / 1850] x 100%
^ If you won your last match ^

[(Your elo x .25) / 1850] x 100%
^ If you lost your last match ^


I've been in the 1800-1900 bracket for a while myself and must say that I run into way too many boosters.

Bump, ask for more.