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1 = √[1] = √[(-1) * (-1)] = √[-1] * √[-1] = i * i = i² = -1. Thus, 1 = -1. QED

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xzarion ?? Senior Member
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02-24-2013

.

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Griftrix Griftrix's Avatar ?? Senior Animation Engineer
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02-24-2013

http://www.regentsprep.org/Regents/m...cyresource.htm

Spoiler alert, this points out the fallacy in the "proof".

QED.

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Tejesh ?? Senior Member
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02-24-2013

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Originally Posted by Griftrix View Post
Oh you.

.999999999999 repeating is or is not 1?

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Gespens ?? Senior Member
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02-24-2013

Well, he is not exactly wrong, just technically.

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Griftrix Griftrix's Avatar ?? Senior Animation Engineer
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02-24-2013

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Originally Posted by Tejesh View Post
Oh you.

.999999999999 repeating is or is not 1?
It is. But you will only understand that if you understand that 0.9 repeating is a real number, not something that approaches a number. Without that understanding it may be hard to grasp.

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Griftrix Griftrix's Avatar ?? Senior Animation Engineer
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02-24-2013

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Originally Posted by Gespens View Post
Well, he is not exactly wrong, just technically.
In mathematics, isn't technically wrong, exactly wrong?

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Blugyblug ?? Senior Member
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02-24-2013

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It is. But you will only understand that if you understand that 0.9 repeating is a real number, not something that approaches a number. Without that understanding it may be hard to grasp.
P(cp, c/p) lies on the rectangular hyperbola xy=c^2. Lines drawn from the foci S and S' are perpendicular to tangent at P, and meet the hyperbola at A, B, C, D.

find the coordinates of point A.

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XAlFias ?? Senior Member
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02-24-2013

Go away math !!! Stop following meeeeeeeeeeeeee !!!!!!!!!!!!!

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A Gay Squirrel ?? Senior Member
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02-24-2013

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Originally Posted by Gespens View Post
Well, he is not exactly wrong, just technically.
No; he is exactly wrong. The square root of 1 has 2 solutions: -1 and 1. By ignoring -1, which is the solution he's supposed to use, all the equations he made after are false.

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omegademan ?? Senior Member
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02-24-2013

Wait, so if someone owes me $2 how does this get my money any faster?

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